SQLHUB Telegram 2044
🧩 Задача из интервью TikTok по SQL

Найдите пользователей, которые не подтвердили регистрацию в день регистрации, но подтвердили на следующий день.

Исходные таблицы:
- emails(email_id, user_id, signup_date)
- texts(text_id, email_id, signup_action {'Confirmed','Not confirmed'}, action_date)

Решение (универсально для Postgres/MySQL):

SELECT DISTINCT e.user_id
FROM emails e
WHERE EXISTS (
SELECT 1
FROM texts t1
WHERE t1.email_id = e.email_id
AND t1.signup_action = 'Confirmed'
AND DATE(t1.action_date) = DATE(e.signup_date + INTERVAL '1 day') -- подтвердил на 2-й день
)
AND NOT EXISTS (
SELECT 1
FROM texts t0
WHERE t0.email_id = e.email_id
AND t0.signup_action = 'Confirmed'
AND DATE(t0.action_date) = DATE(e.signup_date) -- не подтвердил в день регистрации
);


Вариант через агрегацию (Postgres)🧩️


SELECT e.user_id
FROM emails e
JOIN texts t ON t.email_id = e.email_id
GROUP BY e.user_id, e.signup_date
HAVING COUNT(*) FILTER (
WHERE t.signup_action = 'Confirmed' AND DATE(t.action_date) = DATE(e.signup_date)
) = 0
AND COUNT(*) FILTER (
WHERE t.signup_action = 'Confirmed' AND DATE(t.action_date) = DATE(e.signup_date + INTERVAL '1 day')
) >= 1;


@sqlhub
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🧩 Задача из интервью TikTok по SQL

Найдите пользователей, которые не подтвердили регистрацию в день регистрации, но подтвердили на следующий день.

Исходные таблицы:
- emails(email_id, user_id, signup_date)
- texts(text_id, email_id, signup_action {'Confirmed','Not confirmed'}, action_date)

Решение (универсально для Postgres/MySQL):


SELECT DISTINCT e.user_id
FROM emails e
WHERE EXISTS (
SELECT 1
FROM texts t1
WHERE t1.email_id = e.email_id
AND t1.signup_action = 'Confirmed'
AND DATE(t1.action_date) = DATE(e.signup_date + INTERVAL '1 day') -- подтвердил на 2-й день
)
AND NOT EXISTS (
SELECT 1
FROM texts t0
WHERE t0.email_id = e.email_id
AND t0.signup_action = 'Confirmed'
AND DATE(t0.action_date) = DATE(e.signup_date) -- не подтвердил в день регистрации
);


Вариант через агрегацию (Postgres)🧩️


SELECT e.user_id
FROM emails e
JOIN texts t ON t.email_id = e.email_id
GROUP BY e.user_id, e.signup_date
HAVING COUNT(*) FILTER (
WHERE t.signup_action = 'Confirmed' AND DATE(t.action_date) = DATE(e.signup_date)
) = 0
AND COUNT(*) FILTER (
WHERE t.signup_action = 'Confirmed' AND DATE(t.action_date) = DATE(e.signup_date + INTERVAL '1 day')
) >= 1;


@sqlhub

BY Data Science. SQL hub




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