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🎯 Как настроить Spring Security с кастомной формой логина

Безопасность — базовая вещь. Spring Security по умолчанию кидает вас в дефолтную форму логина. Но в реальности — нужна своя, кастомная.

1️⃣ Добавьте зависимость
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-security</artifactId>
</dependency>


2️⃣ Создайте SecurityConfig
@Configuration
@EnableWebSecurity
public class SecurityConfig {

@Bean
public SecurityFilterChain securityFilterChain(HttpSecurity http) throws Exception {
http
.authorizeHttpRequests(auth -> auth
.requestMatchers("/login", "/css/**").permitAll()
.anyRequest().authenticated()
)
.formLogin(form -> form
.loginPage("/login")
.defaultSuccessUrl("/dashboard", true)
.permitAll()
)
.logout(logout -> logout
.logoutSuccessUrl("/login?logout")
);

return http.build();
}

@Bean
public UserDetailsService userDetailsService() {
var user = User.withUsername("admin")
.password("{noop}admin123") // Для простоты, без шифрования
.roles("ADMIN")
.build();
return new InMemoryUserDetailsManager(user);
}
}


3️⃣ Создайте кастомную HTML-форму

src/main/resources/templates/login.html (если используете Thymeleaf):
<!DOCTYPE html>
<html>
<head><title>Login</title></head>
<body>
<h2>Login</h2>
<form method="post" action="/login">
<label>Username: <input type="text" name="username" /></label><br/>
<label>Password: <input type="password" name="password" /></label><br/>
<button type="submit">Login</button>
</form>
</body>
</html>


4️⃣ Реализуете контроллер
@RestController
public class DashboardController {

@GetMapping("/dashboard")
public String dashboard() {
return "Welcome to the dashboard!";
}
}


🐸 Библиотека джависта #буст
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🎯 Как настроить Spring Security с кастомной формой логина

Безопасность — базовая вещь. Spring Security по умолчанию кидает вас в дефолтную форму логина. Но в реальности — нужна своя, кастомная.

1️⃣ Добавьте зависимость

<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-security</artifactId>
</dependency>


2️⃣ Создайте SecurityConfig
@Configuration
@EnableWebSecurity
public class SecurityConfig {

@Bean
public SecurityFilterChain securityFilterChain(HttpSecurity http) throws Exception {
http
.authorizeHttpRequests(auth -> auth
.requestMatchers("/login", "/css/**").permitAll()
.anyRequest().authenticated()
)
.formLogin(form -> form
.loginPage("/login")
.defaultSuccessUrl("/dashboard", true)
.permitAll()
)
.logout(logout -> logout
.logoutSuccessUrl("/login?logout")
);

return http.build();
}

@Bean
public UserDetailsService userDetailsService() {
var user = User.withUsername("admin")
.password("{noop}admin123") // Для простоты, без шифрования
.roles("ADMIN")
.build();
return new InMemoryUserDetailsManager(user);
}
}


3️⃣ Создайте кастомную HTML-форму

src/main/resources/templates/login.html (если используете Thymeleaf):
<!DOCTYPE html>
<html>
<head><title>Login</title></head>
<body>
<h2>Login</h2>
<form method="post" action="/login">
<label>Username: <input type="text" name="username" /></label><br/>
<label>Password: <input type="password" name="password" /></label><br/>
<button type="submit">Login</button>
</form>
</body>
</html>


4️⃣ Реализуете контроллер
@RestController
public class DashboardController {

@GetMapping("/dashboard")
public String dashboard() {
return "Welcome to the dashboard!";
}
}


🐸 Библиотека джависта #буст

BY Библиотека джависта | Java, Spring, Maven, Hibernate




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