CHALLENGINGHARDQUESTIONS Telegram 10691
Forwarded from सक्षम ठाकुर (बन्ना ''सा")
10/3= a(a+5)/2a+5
3a²+15a= 20a+50
3a²-5a-50= 0
a= 5
b= 10



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10/3= a(a+5)/2a+5
3a²+15a= 20a+50
3a²-5a-50= 0
a= 5
b= 10

BY Quant-Entelechy(The ELITES)


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