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Answer to Q83

1, 3, 8, 19, x. What is x?

Finding the difference between this series:

3 - 1 = 2
8 - 3 = 5
19 - 8 = 11
x - 19 = y (eqn i)

We have a new series here:

2, 5, 11, y and there still didn't seem to be a clear relationship between them, so we find their difference again.

5 - 2 = 3
11 - 5 = 6
y - 11 = z (eqn ii)

New series 3, 6, z so here we have our relationship. First element is 3, second element is twice of first element (2x3 = 6), so

z = 6 x 2 = 12

Putting z into eqn ii
y - 11 = 12
y = 12 + 11 = 23

Putting y into eqn i
x - 19 = 23
x = 23 + 19 = 42

Answer: 42

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866 viewsDec 15, 2019 at 18:46

Answer to Q83

1, 3, 8, 19, x. What is x?

Finding the difference between this series:

3 - 1 = 2
8 - 3 = 5
19 - 8 = 11
x - 19 = y (eqn i)

We have a new series here:

2, 5, 11, y and there still didn't seem to be a clear relationship between them, so we find their difference again.

5 - 2 = 3
11 - 5 = 6
y - 11 = z (eqn ii)

New series 3, 6, z so here we have our relationship. First element is 3, second element is twice of first element (2x3 = 6), so

z = 6 x 2 = 12

Putting z into eqn ii
y - 11 = 12
y = 12 + 11 = 23

Putting y into eqn i
x - 19 = 23
x = 23 + 19 = 42

Answer: 42

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