Advanced Maths collection

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bc=-a(b+c)
ab=-c(b+a)
ac=-b(a+c)

a²/(a²-bc)+b²/(b²-ac)+c²/(c²-ab)=
a²/(a²+a(b+c))+b²/(b²+b(a+c))+c²/(c²+c(b+a))=
a/(a+b+c)+b/(a+b+c)+c/(a+b+c)=
(a+b+c)/(a+b+c)=1

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4.08K viewsAzizakhon Turakhujaeva, Nov 17, 2021 at 15:30

bc=-a(b+c)
ab=-c(b+a)
ac=-b(a+c)

a²/(a²-bc)+b²/(b²-ac)+c²/(c²-ab)=
a²/(a²+a(b+c))+b²/(b²+b(a+c))+c²/(c²+c(b+a))=
a/(a+b+c)+b/(a+b+c)+c/(a+b+c)=
(a+b+c)/(a+b+c)=1

BY Advanced Maths collection